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    Natural transformations and natural isomorphisms

    D-DEFNATTR

    (natural transformation)

    Let \(F, G: \mcc \to \mcd\) be covariant functors. A natural transformation \(F \to G\) is the data of maps \(F(X) \to G(X)\) in \(\mcd\) for all \(X \in \mcc\), such that for every \(f: X \to Y\) in \(\mcc\) the square \[ \begin{matrix} F(X) & \to & G(X) \\ \downarrow & & \downarrow \\ F(Y) & \to & G(Y) \end{matrix} \] commutes. For contravariant functors one asks the analogous square, with the vertical arrows reversed, to commute.

    (natural isomorphism)

    A natural isomorphism \(F \to G\) is a natural transformation such that \(F(X) \to G(X)\) is an isomorphism for every object \(X\).

    Natural transformations are the morphisms of the functor category \(\mcd^{\mcc}\), and the natural isomorphisms are its isomorphisms: if each component \(F(X)\to G(X)\) is an isomorphism, the inverse maps \(G(X) \to F(X)\) form a natural transformation.

    On finite-dimensional vector spaces over a field \(k\), the evaluation maps \(V\to V^{\vee\vee}\) form a natural isomorphism from the identity functor to the double-dual functor. An isomorphism \(V\cong V^\vee\) exists for each \(V\) but depends on a choice, such as a basis; the dual is contravariant, so the identity functor and \(V\mapsto V^\vee\) are not functors of the same variance.

    What is a natural transformation between two functors?
    What is a natural isomorphism, and in what category is it the notion of isomorphism?

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