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    Seifert-van Kampen when one inclusion is surjective

    E-1DM8W

    Area
    Topology
    Topics
    Seifert-van Kampen Theorem
    Status
    draft

    Suppose that \(i_2\) is surjective.

    1. Show that \(j_1\) induces an epimorphism

    \[ h: \pi_1(U, x_0)/M \to \pi_1(X, x_0), \]

    where \(M\) is the least normal subgroup of \(\pi_1(U, x_0)\) containing \(i_1(\ker i_2)\). [Hint: Show \(j_1\) is surjective.]

    1. Show that \(h\) is an isomorphism. [Hint: Let \(H = \pi_1(U, x_0)/M\). Let \(\phi_1: \pi_1(U, x_0) \to H\) be the projection. Use the fact that \(\pi_1(U \cap V, x_0)/\ker i_2\) is isomorphic to \(\pi_1(V, x_0)\) to define a homomorphism \(\phi_2: \pi_1(V, x_0) \to H\). Use Theorem 70.1 to define a left inverse for \(h\).]
    Solution

    Goal: Prove that when the inclusion homomorphism \(i_2: \pi_1(U \cap V, x_0) \to \pi_1(V, x_0)\) is surjective, \(\pi_1(X, x_0) \cong \pi_1(U, x_0)/M\), where \(M\) is the normal closure of \(i_1(\ker i_2)\).

    1. Part (a): Surjectivity of \(j_1\) and existence of the epimorphism \(h\).Proof:

    1.1. By the Seifert-van Kampen theorem, the images of \((j_1)_*\) and \((j_2)_*\) generate \(\pi_1(X, x_0)\), and \((j_1)_* \circ (i_1)_* = (j_2)_* \circ (i_2)_*\).

    1.2. For any \(v \in \pi_1(V, x_0)\), surjectivity of \((i_2)_*\) guarantees the existence of \(w \in \pi_1(U \cap V, x_0)\) such that \((i_2)_*(w) = v\).

    1.3. Then \((j_2)_*(v) = (j_2)_*((i_2)_*(w)) = (j_1)_*((i_1)_*(w)) \in \operatorname{im}((j_1)_*)\).

    1.4. Thus \(\operatorname{im}((j_2)_*) \subseteq \operatorname{im}((j_1)_*)\), which implies \(\operatorname{im}((j_1)_*) = \pi_1(X, x_0)\), so \((j_1)_*\) is surjective.

    1.5. For any \(w \in \ker((i_2)_*)\), \((j_1)_*((i_1)_*(w)) = (j_2)_*((i_2)_*(w)) = (j_2)_*(1) = 1\).

    1.6. Thus \((i_1)_*(\ker(i_2)_*) \subseteq \ker((j_1)_*)\). Since \(\ker((j_1)_*)\) is normal, the normal closure \(M \subseteq \ker((j_1)_*)\).

    1.7. By the First Isomorphism Theorem, \((j_1)_*\) factors through the quotient to define an epimorphism:\[h: \pi_1(U, x_0)/M \to \pi_1(X, x_0), \quad h([u]) = (j_1)_*(u).\]

    2. Part (b): \(h\) is an isomorphism (construction of a left inverse via pushout).Proof:

    2.1. Let \(H = \pi_1(U, x_0)/M\), and let \(\phi_1: \pi_1(U, x_0) \to H\) be the canonical projection homomorphism.

    2.2. Consider the homomorphism \(\phi_1 \circ (i_1)_*: \pi_1(U \cap V, x_0) \to H\). For any \(w \in \ker((i_2)_*)\), \((i_1)_*(w) \in M = \ker(\phi_1)\), so \(\ker((i_2)_*) \subseteq \ker(\phi_1 \circ (i_1)_*)\).

    2.3. Since \((i_2)_*: \pi_1(U \cap V, x_0) \to \pi_1(V, x_0)\) is surjective, \(\pi_1(U \cap V, x_0)/\ker((i_2)_*) \cong \pi_1(V, x_0)\).

    2.4. Therefore \(\phi_1 \circ (i_1)_*\) factors through \((i_2)_*\) to yield a unique homomorphism \(\phi_2: \pi_1(V, x_0) \to H\) satisfying:\[\phi_2 \circ (i_2)_* = \phi_1 \circ (i_1)_*.\]

    2.5. By the universal property of the Seifert-van Kampen theorem (Theorem 70.1), there exists a unique homomorphism \(g: \pi_1(X, x_0) \to H\) such that \(g \circ (j_1)_* = \phi_1\) and \(g \circ (j_2)_* = \phi_2\).

    2.6. For any \([u] \in H\):\[(g \circ h)([u]) = g((j_1)_*(u)) = \phi_1(u) = [u].\]

    2.7. Thus \(g \circ h = \operatorname{id}_H\), so \(h\) has a left inverse \(g\) and is therefore injective.

    2.8. Being both surjective and injective, \(h\) is an isomorphism of groups. Q.E.D.