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    Products of Hausdorff spaces are Hausdorff

    E-E3JL6

    Area
    Topology
    Topics
    Hausdorff Spaces, Product Topology
    Seen at
    WESLEYAN
    Years
    2008
    Status
    draft

    Show that the product of two Hausdorff spaces is Hausdorff.

    Solution

    Let \(X\) and \(Y\) be Hausdorff, and let \(p_1=(x_1,y_1)\) and \(p_2=(x_2,y_2)\) be distinct points of \(X\times Y\), so that \(x_1\ne x_2\) or \(y_1\ne y_2\).

    1. If \(x_1\ne x_2\), then \(p_1\) and \(p_2\) have disjoint open neighborhoods.

    Choose disjoint open \(U_1\ni x_1\) and \(U_2\ni x_2\) in \(X\). Then \(U_1\times Y\) and \(U_2\times Y\) are open in \(X\times Y\), contain \(p_1\) and \(p_2\), and \((U_1\times Y)\cap(U_2\times Y)=(U_1\cap U_2)\times Y=\varnothing\).

    2. If \(y_1\ne y_2\), then \(p_1\) and \(p_2\) have disjoint open neighborhoods.

    Choose disjoint open \(V_1\ni y_1\) and \(V_2\ni y_2\) in \(Y\); then \(X\times V_1\) and \(X\times V_2\) are disjoint open neighborhoods of \(p_1\) and \(p_2\), as in step 1.

    3. Q.E.D.

    Steps 1 and 2 cover both cases.