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    Holomorphic functions on a domain: $fg\equiv 0$ implies $f\equiv 0$ or $g\equiv 0$

    E-FXYTL

    Area
    Complex Analysis
    Topics
    Identity Theorem, Zeros
    Status
    draft

    Show that if \(fg \equiv 0\) on a domain \(\Omega\) then either \(f\equiv 0\) or \(g\equiv 0\).

    Solution

    If \(f\not\equiv 0\), there is a point \(z_0\) where \(f(z_0)\neq 0\), and thus a neighborhood \(U\ni z_0\) where \(f\) is nonvanishing. This forces \(g\equiv 0\) on \(U\), however \(U\) is a set with a limit point, so \(g\equiv 0\) on \(\Omega\) by the identity principle.