Show that if \(fg \equiv 0\) on a domain \(\Omega\) then either \(f\equiv 0\) or \(g\equiv 0\).
Solution
If \(f\not\equiv 0\), there is a point \(z_0\) where \(f(z_0)\neq 0\), and thus a neighborhood \(U\ni z_0\) where \(f\) is nonvanishing. This forces \(g\equiv 0\) on \(U\), however \(U\) is a set with a limit point, so \(g\equiv 0\) on \(\Omega\) by the identity principle.