Show that the one-point compactification of \(\mathbb{R}\) is homeomorphic with the circle \(S^1\).
Solution
Identify \(S^1\) with the unit circle in \(\mathbb R^2\), and choose the point \(N=(0,1)\). Stereographic projection \[ \sigma:S^1\setminus\{N\}\to\mathbb R \] is a homeomorphism. Hence \(\sigma^{-1}:\mathbb R\to S^1\setminus\{N\}\) is a homeomorphism.
Extend it by sending the point at infinity in the one-point compactification \(\mathbb R^*=\mathbb R\cup\{\infty\}\) to \(N\). To check continuity at infinity, note that a neighborhood of \(N\) has compact complement in \(S^1\setminus\{N\}\); under stereographic projection this complement corresponds to a compact subset of \(\mathbb R\). Therefore its preimage in \(\mathbb R^*\) is a neighborhood of \(\infty\). The extension is a continuous bijection from compact \(\mathbb R^*\) to Hausdorff \(S^1\), hence a homeomorphism.