\[ \int_{1}^{\infty} \frac{d x}{x \sqrt{x^{2}-1}} = {\pi \over 2} .\]
Solution
The integral of $1/(x\sqrt{x^2-1})$ over $[1,\infty)$
E-Z66NC
- Area
- Complex Analysis
- Topics
- Complex Logarithm, Contour Integration, Integrals, Residues
- Status
- draft
E-Z66NC
\[ \int_{1}^{\infty} \frac{d x}{x \sqrt{x^{2}-1}} = {\pi \over 2} .\]