Search the corpus

    Contrapositive and converse of: a local minimum at $a$ implies $f'(a)=0$ or nondifferentiability at $a$

    P-ABRWU

    Area
    Prelim
    Topics
    Differentiation, Logic and Quantifiers
    Seen at
    UGA
    Years
    2004
    Status
    draft

    Let \(f:\mathbb{R}\to\mathbb{R}\) be a function and let \(a\) be a real number. Let \(S\) be the statement “If \(f\) has a local minimum at \(a\), then \(f'(a)=0\) or \(f\) is not differentiable at \(a\)”.

    1. Write the contrapositive of \(S\).
    2. Write the converse of \(S\).
    3. Which of the statements in (a) and (b) are true? If either statement is false, give a counterexample.
    Solution

    Write \[ P:\ f\text{ has a local minimum at }a, \qquad Q:\ f'(a)=0\text{ or }f\text{ is not differentiable at }a. \] The contrapositive is \(\neg Q\Rightarrow\neg P\), namely:

    If \(f\) is differentiable at \(a\) and \(f'(a)\ne0\), then \(f\) does not have a local minimum at \(a\).

    This is true because it is logically equivalent to the original statement \(S\).

    The converse is \(Q\Rightarrow P\), namely:

    If \(f'(a)=0\) or \(f\) is not differentiable at \(a\), then \(f\) has a local minimum at \(a\).

    This is false. For example, \(f(x)=x^3\) at \(a=0\) has \(f'(0)=0\) but no local minimum there. Also \(f(x)=x^{1/3}\) is not differentiable at \(0\) and has no local minimum there.

    Source Collections

    Guide Appearances