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    Distance between disjoint compact sets in $\RR^n$ is attained

    P-BUD7S

    Area
    Complex Analysis
    Topics
    Compactness, Euclidean Spaces, Metric Spaces
    Status
    draft

    Suppose \(A, B \subseteq \RR^n\) are disjoint and compact. Prove that there exist \(a\in A, b\in B\) such that \[ \norm{a - b} = \inf\theset{\norm{x-y} \suchthat x\in A,\, y\in B} .\]

    Solution

    Define a function \[ d: A \cross B &\to \RR \\ (x, y) &\mapsto \norm{x- y} .\] Then \(d\) is a continuous function on a compact topological space (where the product is compact by Tychonoff), and the extreme value theorem applies: \(d\) attains its min/max for some pair \((a, b)\) in its domain.

    Note that disjointness just guarantees that \(\norm{a-b}>0\), since \(\norm{a-b} = 0 \implies a=b\) and \(A \intersect B = \emptyset\).