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    Diagonalizable does not imply distinct eigenvalues

    P-CDRT6

    Area
    Algebra
    Topics
    Counterexamples, Diagonalization, Eigenvalues and Eigenvectors
    Status
    draft
    • Does diagonalizable imply distinct eigenvalues?
    Solution

    No. For example, the identity matrix \[ I_2=\begin{pmatrix}1&0\\0&1\end{pmatrix} \] is already diagonal, hence diagonalizable, but it has only one eigenvalue, namely \(1\), with algebraic multiplicity \(2\).

    More generally, a diagonalizable matrix may have repeated diagonal entries. Diagonalizability means that the vector space has a basis of eigenvectors; it does not require the corresponding eigenvalues to be distinct.