- Compute \(\pi_1(S^1 \cross S^1)\)
Solution
1. For path-connected spaces, fundamental groups commute with products:\[\pi_1(X\times Y,(x_0,y_0))\cong\pi_1(X,x_0)\times\pi_1(Y,y_0).\]
A loop in a product is exactly a pair of loops, and homotopies are likewise coordinatewise.
2. Since \(\pi_1(S^1)\cong\mathbb Z\),\[\boxed{\pi_1(S^1\times S^1)\cong\mathbb Z\times\mathbb Z.}\]
Apply 1 to the two circle factors.