Solution: \(u = \frac{1}{x}\), \(du = -\frac{1}{x^2}\,dx\)
Used 2018
Solution
For a continuous function \(\Phi\), the substitution \(u=1/x\), \(du=-x^{-2}\,dx\) gives \[ \int \frac{\Phi(1/x)}{x^2}\,dx=-\int \Phi(u)\,du. \]
The substitution $u=1/x$
P-DH6CX
- Area
- Prelim
- Topics
- Integrals, u-Substitution
- Status
- draft