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    The torsion subset of a module over an integral domain is a submodule

    P-GQZ1O

    Area
    Algebra
    Topics
    Integral Domains, Modules, Torsion
    Status
    draft

    Let \(R\) be an integral domain and \(M\) an \(R\)-module. Define \[ T(M)=\{m\in M:rm=0\text{ for some }0\ne r\in R\}. \] Prove that \(T(M)\) is an \(R\)-submodule of \(M\).

    Solution

    1. One has \(0\in T(M)\).

    For any nonzero \(r\in R\), \(r0=0\).

    2. If \(m,n\in T(M)\) and \(c\in R\), then \(cm+n\in T(M)\).

    Choose nonzero annihilators \(a,b\in R\) with \[ am=0, \qquad bn=0. \] Since \(R\) is a domain, \[ ab\ne0. \] Then \[ ab(cm+n) =bc(am)+a(bn) =0. \] Thus \(cm+n\) is torsion.

    3. Therefore \(T(M)\le M\).

    2. The domain hypothesis is used exactly to ensure that the product of two nonzero annihilators is still nonzero.