Evaluate \[ \int 2018^x\,dx. \]
Solution
Since \[ \frac{d}{dx}2018^x=(\ln 2018)2018^x, \] we have \[ \boxed{\int 2018^x\,dx=\frac{2018^x}{\ln 2018}+C.} \]
$\int 2018^x\,dx$
P-JHXZS
- Area
- Prelim
- Topics
- Integrals
- Status
- draft
P-JHXZS
Evaluate \[ \int 2018^x\,dx. \]
Since \[ \frac{d}{dx}2018^x=(\ln 2018)2018^x, \] we have \[ \boxed{\int 2018^x\,dx=\frac{2018^x}{\ln 2018}+C.} \]