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    Normality of subgroups is not transitive

    P-L7OQW

    Area
    Algebra
    Topics
    Counterexamples, Normal Subgroups, Subgroups
    Status
    draft

    Give an example of subgroups \[ H\trianglelefteq K\trianglelefteq G \] with \(H\) not normal in \(G\).

    Solution

    Take \[ G=A_4, \qquad K=V_4=\{e,(12)(34),(13)(24),(14)(23)\}, \] and \[ H=\langle(12)(34)\rangle. \]

    The subgroup \(K\) is normal in \(A_4\): it consists of the identity together with all three double transpositions, and conjugation preserves cycle type.

    The subgroup \(H\) has order \(2\). Since \(K\cong C_2\times C_2\) is abelian, every subgroup of \(K\) is normal, so \[ H\trianglelefteq K. \]

    But \(H\) is not normal in \(A_4\). For example, \[ (123)(12)(34)(123)^{-1}=(23)(14), \] which is not in \(H\).

    Thus \[ H\trianglelefteq K\trianglelefteq G \] does not imply \(H\trianglelefteq G\).