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    Prime elements of $\ZZ[i]$

    P-QSHZ6

    Area
    Algebra
    Topics
    Factorization, Number Theory, Prime Ideals
    Status
    draft

    Classify the prime elements of the Gaussian integers \(\ZZ[i]\), up to multiplication by units.

    Solution

    The units of \(\ZZ[i]\) are \[ \{\pm1,\pm i\}. \] Up to these units, the Gaussian primes are exactly the following.

    1. The ramified prime above \(2\):\[ 1+i, \]with\[ 2=-i(1+i)^2. \]

    2. Rational primes \(p\equiv3\pmod4\).

    Such a prime remains irreducible in \(\ZZ[i]\). If it factored nontrivially, taking norms would write \[ p^2=N(\alpha)N(\beta) \] with both norms greater than \(1\), forcing one factor to have norm \(p\). But \[ a^2+b^2=p \] has no solution when \(p\equiv3\pmod4\).

    3. Gaussian integers \(a+bi\) with both coordinates nonzero and\[ a^2+b^2=p \]a rational prime.

    Their norm is the rational prime \(p\). Since the norm is multiplicative, any factorization would force one factor to have norm \(1\), hence be a unit. Thus \(a+bi\) is prime.

    For rational primes \(p\equiv1\pmod4\), Fermat’s two-squares theorem gives \[ p=a^2+b^2=(a+bi)(a-bi), \] so \(p\) itself is not Gaussian prime; the factors \(a\pm bi\) are.

    Equivalently, a nonunit \(a+bi\) is Gaussian prime iff either - one of \(a,b\) is zero and the absolute value of the other is a rational prime congruent to \(3\pmod4\), or - both are nonzero and \(a^2+b^2\) is a rational prime.