Evaluate \[ \int\frac{x^2}{1+x^6}\,dx. \]
Solution
Let \(u=x^3\), so \(du=3x^2\,dx\). Therefore \[ \boxed{\int\frac{x^2}{1+x^6}\,dx=\frac13\arctan(x^3)+C.} \]
$\int\frac{x^2}{1+x^6}\,dx$
P-SZNKD
- Area
- Prelim
- Topics
- Integrals, u-Substitution
- Status
- draft