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    $\int_0^{2\pi}\frac{d\theta}{1+a\cos\theta}$ for $|a|<1$

    P-TRIV-CA18

    Area
    Complex Analysis
    Status
    draft
    Contents

    Compute \(\displaystyle\int_0^{2\pi} \frac{d\theta}{1 + a\cos\theta}\,\mathrm{d}x\) with \(|a| < 1\);

    Erratum: the trailing \(\mathrm{d}x\) is printed in the source after \(d\theta\) and is a typo; the integral is \(\int_0^{2\pi} \frac{d\theta}{1 + a\cos\theta}\) with integration variable \(\theta\) and no \(x\) in the integrand.

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