Show that \(\delta ( x ) = \operatorname* { l i m } _ { \epsilon \to 0 } \operatorname { I m } \frac { 1 } { \pi } \frac { 1 } { x - i \epsilon }\)
$\delta(x)$ as the limit of $\frac1\pi\operatorname{Im}\frac{1}{x-i\epsilon}$
P-TRIV-DE32
- Area
- Prelim
- Status
- draft