Evaluate \[ \int\frac{x+1}{x^2+2x+3}\,dx. \]
Solution
Let \(u=x^2+2x+3\), so \(du=2(x+1)\,dx\). Therefore \[ \boxed{\int\frac{x+1}{x^2+2x+3}\,dx=\frac12\ln(x^2+2x+3)+C.} \]
Antiderivative of $\frac{x+1}{x^2+2x+3}$
P-UNHGI
- Area
- Prelim
- Topics
- Integrals, u-Substitution
- Status
- draft