Find the number of solutions to the following equation on \(\abs{z} < 1\): \[ 6z^3 + 1 = -e^z .\]
Solution
Write \(f(z) \da 6z^3 + 1 + e^z\).
- Small: \(m(z) = e^z + 1\)
- Large: \(M(z) = 6z^3\)
- The estimate: \[ \abs{m(z)} = \abs{e^z + 1} \leq e^{\Re(z)} + 1 \leq e^{\abs{z}} + 1 = e+1 < 6 = \abs{6z^3} ,\] so \(3 = Z_M = Z_f\).