Suppose \(f=u+iv\) is analytic on a domain \(D\subset\mathbb C\) and \[ v(z)=u(z)^2 \qquad(z\in D). \] Show that \(f\) is constant on \(D\).
An analytic function satisfying $v=u^2$ is constant
P-WESCA04-P4
- Area
- Complex Analysis
- Seen at
- WESLEYAN
- Years
- 2004
- Status
- draft