Let \(C\) be a smooth projective curve of genus \(g \geq 2\) over \(k = \kbar\). Then \(\Aut C\) is finite, and in characteristic zero \[ \size \Aut C \leq 84(g-1) . \] If \(C\) is non-hyperelliptic, every automorphism of \(C\) is induced by a linear automorphism of the ambient \(\PP^{g-1}\) of the canonical embedding; for \(g = 3\) this says \(\Aut C\) is the subgroup of \(\PGL_3\) preserving the plane quartic. The general curve of genus \(g \geq 3\) has \(\Aut C = 1\).
Finiteness follows from the vanishing of infinitesimal automorphisms together with a projective realization of the automorphism group. The reason: \(T_C \cong \dualof{\omega_C}\) has degree \(2-2g < 0\), so \(h^0(T_C) = 0\) and there are no infinitesimal automorphisms; \(\Aut C\) is an algebraic group of dimension \(0\). The argument that makes it a finite group rather than merely \(0\)-dimensional runs through the canonical embedding: \(\omega_C\) is intrinsic, so any automorphism carries \(\abs{K}\) to itself and acts on \(\PP^{g-1} = \PP(\dualof{H^0(\omega_C)})\). For non-hyperelliptic \(C\) the canonical map is an embedding, so \(\Aut C\) is exactly the closed subgroup of \(\PGL_g\) stabilizing the canonical curve, hence an algebraic group of dimension \(0\) in a variety, hence finite. For hyperelliptic \(C\) run the same argument with \(\abs{3K}\), which is very ample. The genus-\(3\) statement is this with \(g-1 = 2\): automorphisms are restrictions of automorphisms of \(\PP^2\), so a plane quartic has no automorphisms beyond the linear ones visible in its equation.
The bound comes from Riemann–Hurwitz applied to the quotient \(C \to C/G\) with \(G = \Aut C\) of order \(n\). Writing \(g'\) for the genus of the quotient and \(e_1,\ldots,e_r\) for the ramification indices of the branch points, \[ 2g-2 = n\left( 2g'-2 + \sum_{i=1}^r \left(1 - \frac{1}{e_i}\right) \right) , \] so \(n\) is largest when the bracket is smallest, and the smallest positive value the bracket can take is \(\frac{1}{42}\), attained at \(g' = 0\) with three branch points of orders \((2,3,7)\). That gives \(n \leq 42(2g-2) = 84(g-1)\). The bound is sharp: the Klein quartic \(x^3 y + y^3 z + z^3 x = 0\) has \(g = 3\) and \(\Aut = \PSL_2(\FF_7)\) of order \(168 = 84 \cdot 2\), and it is a plane quartic, so its automorphisms are linear as the previous paragraph requires. The characteristic hypothesis is not decorative: the count of \(1 - 1/e_i\) is the tame formula, and in characteristic \(p\) wild ramification breaks the bound.
The two ends of this card are what the moduli statements need. Finiteness of \(\Aut C\) is why the \(\PGL_3\) orbits in the plane-quartic count are \(8\)-dimensional, which is what makes \(\dim \mathcal{M}_3 = 14-8\) come out right. Nontriviality of \(\Aut C\) for some curve is the obstruction to a fine moduli space, and no genus escapes it: the general curve of genus \(g \geq 3\) has no automorphisms, but every hyperelliptic curve carries its involution and the hyperelliptic locus is nonempty in every genus. At \(g = 2\) there is no general case to appeal to at all, since every genus-\(2\) curve is hyperelliptic.
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D-CRVHYPHyperelliptic curves and their canonical mapsuses