Riemann--Lebesgue lemma: $\widehat f$ is bounded, continuous, and vanishes at infinity

The Fourier transform of an $L^1$ function is bounded, continuous, and decays to zero at infinity.Suggest a slogan

Let $f\in L^1(\RR^n)$. Then its Fourier transform $\widehat f$ is continuous on $\RR^n$, satisfies $\sup_{\xi\in\RR^n}\abs{\widehat f(\xi)}\leq\norm{f}_1$, and \[ \widehat f(\xi)\to0 \quad\text{as } \abs{\xi}\to\infty . \]

State the Riemann-Lebesgue lemma.