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    Finite equals proper plus quasi-finite

    PR-MORFINCHAR

    Over locally Noetherian schemes, finite means proper plus quasi-finite, equivalently proper with finite fibres.Suggest a slogan

    Let \(\pi \colon X \to Y\) be a morphism of schemes.

    1. \(\pi\) is finite if and only if it is integral and locally of finite type.

    2. If \(\pi\) is finite, then it is quasi-finite: every fibre is a finite discrete set [@Har10a, Exercise II.3.5].

    3. If \(\pi\) is finite, then \(X \cong \operatorname{\mathbf{Proj}}_Y \mathcal{S}\) over \(Y\) for a quasicoherent graded \(\OO_Y\)-algebra \(\mathcal{S}\) generated in degree \(1\) by the finite type module \(\mathcal{S}_1\); in particular \(\pi\) is projective in the sense of D-SCHRELSPECPROJ, and proper.

    4. A morphism of locally Noetherian schemes is finite exactly when it is proper and quasi-finite, equivalently proper with finite fibres [@Har10a, Exercise III.11.2]. Without Noetherian hypotheses: finite exactly when proper, locally of finite presentation, and with finite fibres.

    This characterization converts the module-theoretic definition of finiteness into geometric conditions. The implications are \[ \text{finite} \implies \text{projective} \implies \text{proper} \implies \text{universally closed}, \] with none of them reversible: \(\PP^1_k \to \Spec k\) is projective and not finite, and complete non-projective threefolds give proper morphisms to a point that are not projective.

    The converse direction, proper plus finite fibres giving finite, recognizes normalization maps and proper zero-dimensional-fibre morphisms as finite.

    Give a criterion for a morphism to be finite.
    How are finite, proper, and projective related?

    Dependencies

    • D-MORFINFinite morphisms, and finite against finite typeuses
    • D-8XX95Proper morphisms and the valuative criteriauses

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