Show that \(h(z) = z + 3 + 2e^z\) has one root in \(\ts{ \Re(z) \leq 0}\).
Solution
Use the following contour:
Take \(g(z) \da 2e^z < f(z) \da f(z) \da z+3\).
$z+3+2e^z$ has one root in $\{\Re z\le 0\}$
E-XQ4BS
- Area
- Complex Analysis
- Topics
- Rouché, Zeros
- Status
- draft