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    Uniform convergence $f_n\to f$ implies $\int_\gamma f_n\to\int_\gamma f$

    E-XXUNZ

    Area
    Complex Analysis
    Topics
    Contour Integration, Sequences of Functions, Uniform Convergence
    Status
    draft

    Show that if \(f_n\to f\) uniformly then \(\int_\gamma f_n\to \int_\gamma f\).

    Solution

    \[ \abs{ \int_\gamma f_n(z) \dz - \int_\gamma f(z) \dz } &= \abs{\int_\gamma f_n(z) - f(z) \dz} \\ &\leq \int_\gamma \abs{f_n - f} \abs{\dz} \\ &\leq \int_\gamma \norm{f_n - f}_{\infty, \gamma} \cdot \abs{\dz} \\ &= \eps \cdot \length(\gamma) \\ &\convergesto{n\to\infty} 0 .\]