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    Radius of convergence

    E-ZQGR5

    Area
    Complex Analysis
    Topics
    Convergence Tests, Power Series
    Status
    draft

    Find the radius of convergence of

    • \(\sum a^k z^k\) for \(a\) a constant.

    • \(\sum a^{k^2}z^k\)

    Solution

    By Cauchy–Hadamard, for \(\sum c_kz^k\), \[ {1\over R}=\limsup_{k\to\infty}|c_k|^{1/k}. \]

    For \(c_k=a^k\), \[ {1\over R}=|a|, \] so \[ R= \begin{cases} \infty,&a=0,\\ |a|^{-1},&a\neq0. \end{cases} \]

    For \(c_k=a^{k^2}\), \[ {1\over R} =\limsup_{k\to\infty}|a|^k. \] Hence \[ R= \begin{cases} \infty,&|a|<1,\\ 1,&|a|=1,\\ 0,&|a|>1. \end{cases} \]