Translation invariance of the Lebesgue integral

Translating an $L^1$ function does not change its Lebesgue integral.Suggest a slogan

Let $f\in L^1(\RR^n)$ and $h\in\RR^n$. Then $x\mapsto f(x+h)$ lies in $L^1(\RR^n)$ and \[ \int_{\RR^n} f(x+h)\dx = \int_{\RR^n} f(x)\dx . \]