Continuous maps carry compact subsets to compact subsets.Suggest a slogan
Let \(f\colon X\to Y\) be continuous and \(K\subseteq X\) compact. Then \(f(K)\) is compact [@Mun00].
Continuous image of compact is compact
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Let \(f\colon X\to Y\) be continuous and \(K\subseteq X\) compact. Then \(f(K)\) is compact [@Mun00].